Thanks lots, Ken.
I'm flying off -
Fernando
On Sat, Mar 19, 2011 at 3:48 PM, Ken Norton <ken@xxxxxxxxxxx> wrote:
> So, in the spirit of operational full disclosure...
>
> Here's what I've done in preparation for doing a moon shot with a cell-tower
> that I can get from my own front yard.
>
> Follow along, folks. :)
>
> 1. Identified location of the tower. In this case 41.7417N, 92.7330W.
>
> 2. Identified desired shooting location. In this case 41.7428N, 92.7388W.
>
> 3. Stood at desired shooting location and using the ipad with an
> angle-finder found that the cell-tower antennas were 5 degrees elevation.
>
> 4. Using TPE, I located the photographer location with the red marker and
> the tower with the gray marker. Distance to tower is 1640 feet, bearing 104
> degrees.
>
> 5. Using the Time Adjust slider, I move the moon position line till it
> intersects the tower.
>
> 6. Adjust shooting location until line intersects the tower at 5 degrees
> altitude (elevation).
>
> 7. Note the time, which is 8:20 PM.
>
> 8. Note the place where I start shooting. See trees? See building? See
> parking lot to the east of shooting location? This is all downhill.
>
> 9. The downhill slope is significant!!! I am able to start shooting from the
> top of the slope at the townhouse parking lot and as the moon rises, I move
> to the east, down the hill and into the lower parking lot. By doing so, I
> can keep the moon centered on the antennas for around seven minutes.
>
> When dealing with sunrise or moonrise photos you want the ability to move to
> the east. This will allow you to keep the moon centered on an object longer
> than the very short time it will normally give you. North-south movement
> will help with alignment, but when keeping the moon positioned on an
> elevated object, having the ability to move towards that object will alter
> the elevation angle.
>
> Just doing a quick calculation, the moon diameter will be approximately 0.56
> degrees. My 8-foot wide antenna array will be about 0.31 degrees. So the
> entire antenna array will take up just over half of the moon's diameter.
> Since I'm using 300mm focal length on a Four-Thirds camera, my angle-of-view
> is approximately 3.8 degrees horizontally, so the moon will be about 1/8 of
> the width of the image area.
>
> Anything else?
>
> Don't be a mooncalf.
>
> AG
> --
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>
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